حل المعادلة

Question 1

$8x-5y=70$

$9x+7y=3$

Question 2

$8x-5y=70$

$9x+7y=3$

$\begin{vmatrix} C \end{vmatrix}=\begin{vmatrix} 8 &-5 \\ 9& 7 \end{vmatrix}=8(7)-(-5)9=-56+45=101$

$x=\frac{\begin{vmatrix} 70 &-5 \\ 3& 7 \end{vmatrix}}{101}=\frac{70(7)-3(-5)}{101}=\frac{505}{101}=5$

$y=\frac{\begin{vmatrix} 8 &70 \\ 9& 3 \end{vmatrix}}{101}=\frac{8(3)-70(9)}{101}=\frac{-606}{101}=-6$

$\left ( x,y \right )=\left ( 5,-6 \right )$

يمكنك مشاهدة جميع حلول رياضيات 3 الفصل الثاني المصفوفات مقررات

Ghada Abumaraseh · Answer 1 · 2021-10-06T07:48:12+0000

$8x-5y=70$

$9x+7y=3$

$\begin{vmatrix} C \end{vmatrix}=\begin{vmatrix} 8 &-5 \\ 9& 7 \end{vmatrix}=8(7)-(-5)9=-56+45=101$

$x=\frac{\begin{vmatrix} 70 &-5 \\ 3& 7 \end{vmatrix}}{101}=\frac{70(7)-3(-5)}{101}=\frac{505}{101}=5$

$y=\frac{\begin{vmatrix} 8 &70 \\ 9& 3 \end{vmatrix}}{101}=\frac{8(3)-70(9)}{101}=\frac{-606}{101}=-6$

$\left ( x,y \right )=\left ( 5,-6 \right )$