الاجابة
عوامل كثيرة الحدود : (x – 4)(x + 1)(x – 6)
P(x) = (x2 + x – 4x – 4)(x – 6)
= (x2 – 3x – 4)(x – 6)
= x3 – 3x2 – 4x – 6x2 + 18x + 24
= x3 – 9x2 + 14x + 24